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X – linked recessive type of inheritance

⇐ Предыдущая 123 4 5 6 7 Следующая ⇒

1) Affect the males more then the females;

2) Females inherited the recessive trait only from father;

3) More males than females should exhibit the trait.

4) All sons of a homozygous mutant mother should show the trait, since males recessive their only X chromosome from their mothers.

5) The sons of heterozygous (carrier) mothers should show an approximately 1:1 ratio of normal individuals expressing the trait. There is a 50 % chance that the son would get that disease/trait.

For example, X – linked recessively inherited trait is hemophilia.

I 1 2

II

III

1 – women with normal blood clotting.

2 – man suffers hemophilia.

All children have normal blood. One grandchildren (male, son) suffer from hemophilia.

6) From a mating of a carrier female with a normal male all daughter will be carrier, but half will be carriers. And half the sons of these carrier females will exhibit the trait.

7) A male expressing the trait, when mated with a homozygous normal female, will produce all normal children, but all the female progeny will be carries.

P ♀ X^HX^H x ♂ X^hY

G

X^HY

X^HX^h

F_{1 al}

♀

all normal

If mother is carrier of recessive

P ♀ X^HX^h x ♂ X^HY

G

X^HX^H

X^HY

X^HX^h

X^hY

F;;

♀N ♂N ♀ carrier ♂ hemophilic

⇐ Предыдущая 123 4 5 6 7 Следующая ⇒

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